I guess I posted 50+ times that the earth curvature rate on your globe model is approx. 8 inches per mile squared.Dinsdale wrote:Nah. You've proven beyond any shadow of doubt that you're completely inept when it comes to basic math.
Unless you've renounced your belief that a parabolic function describes the arc of a circle?
And many/most times i posted this link along with it.
https://dizzib.github.io/earth/curve-ca ... t=imperial
Simply plug your numbers in and you can find out how far it is to the horizon, and how many feet of an object will be hidden from sight under the curve of the earth, based on your height -- and your distance from the object you are viewing.
Let's take an example.
There is a mountain which is 13,123 ft (about 4 kilometers) high.
We are on a boat (eyes at water level, we are saying) moving away from the mountain.
When we reach a distance of almost 141 miles (about 226 kilometers), away from the mountain, the very top will have finally disappeared from our view.
This is what we know if we just plug our numbers into the calculator.
It is based on the 8 inches (approx.) per mile squared formula.
Now we have NASA's man, David P. Stern, verifying just what I've said.
Imagine that.
http://www-spof.gsfc.nasa.gov/stargaze/Sstern.htm
http://www-spof.gsfc.nasa.gov/stargaze/Shorizon.htm
In the 2nd link, you can look at the bottom and see that the example I posted is -----> HIS EXAMPLE.
The calculator (and the numbers) I had previously been citing (for many weeks) are accurate.
It's fact.
Now if you want to persist (as you did for many weeks previously) that my math is off, I would recommend that you take this up with NASA.
lol