Cosmo Kramer wrote:frodo_biguns wrote:Cosmo Kramer wrote:
I thought it was Sherman being fired that is going to force Favre into retirement...but you say it's the PornQueens sweep? You are truly a fucking waste of space!
Frodo seek help for your obsession...it clearly has you fucked up!
What will it take for you to put 2x2 together and not come up with 1? I know you are stupid, but my God!!!!!!!!!!
2x2 =1 BAAAAAAAAAAAAAAHAAAAAAAAAAAAAAAAA is that new math being taught in Minnesota? what a fucking idiot!
Are really this stupid? No really? I now understand why you don't have any friends. What a total Douchebag!
Since you didn't get the joke in the first place and I had you no matter what your pathetic answer would have been, I'll explain to your retarded Packer ass.
It is why they got rid of the 2 dollar bill. I know why 0=1 though, so here it is.
How 0! = 1 for reasons that are similar to why
x^0 = 1. Both are defined that way. But there are reasons for these
definitions; they are not arbitrary.
You cannot reason that x^0 = 1 by thinking of the meaning of powers as
"repeated multiplications" because you cannot multiply x zero times.
Similarly, you cannot reason out 0! just in terms of the meaning of
factorial because you cannot multiply all the numbers from zero down
to 1 to get 1.
Mathematicians *define* x^0 = 1 in order to make the laws of exponents
work even when the exponents can no longer be thought of as repeated
multiplication. For example, (x^3)(x^5) = x^8 because you can add
exponents. In the same way (x^0)(x^2) should be equal to x^2 by
adding exponents. But that means that x^0 must be 1 because when you
multiply x^2 by it, the result is still x^2. Only x^0 = 1 makes sense
here.
In the same way, when thinking about combinations we can derive a
formula for "the number of ways of choosing k things from a collection
of n things." The formula to count out such problems is n!/k!(n-k)!.
For example, the number of handshakes that occur when everybody in a
group of 5 people shakes hands can be computed using n = 5 (five
people) and k = 2 (2 people per handshake) in this formula. (So the
answer is 5!/(2! 3!) = 10).
Now suppose that there are 2 people and "everybody shakes hands with
everybody else." Obviously there is only one handshake. But what
happens if we put n = 2 (2 people) and k = 2 (2 people per handshake)
in the formula? We get 2! / (2! 0!). This is 2/(2 x), where x is the
value of 0!. The fraction reduces to 1/x, which must equal 1 since
there is only 1 handshake. The only value of 0! that makes sense here
is 0! = 1.
And so we define 0! = 1.
I'm sorry that you only completed 5th grade math.
