Any math geeks here?
Posted: Thu Jun 17, 2010 4:23 pm
I'm trying to figure out how to add 2+4+6+8+10....up to 730, without literally adding them all like that. Anybody know how that formula works?
TIA
TIA
Do they have to be in that order, and what operations are you restricted to?Screw_Michigan wrote:I'm trying to figure out how to add 2+4+6+8+10....up to 730, without literally adding them all like that. Anybody know how that formula works?
TIA
The one thing I remember about Gauss was that he was able to provide his teacher with an answer to the sum of all the numbers from 1 to 100 in a matter of seconds, which is pretty simple, actually.Wolfman wrote:Wasn't that one of the formulas that Karl Friedrich Gauss figured out in Kindergarten ?
How do you figure?Goober McTuber wrote:I don’t know how to do it with a formula, but I do know from a 20-second exercise with a calculator that that pattern will never land on 730.
It's like this.Mikey wrote:Do they have to be in that order, and what operations are you restricted to?Screw_Michigan wrote:I'm trying to figure out how to add 2+4+6+8+10....up to 730, without literally adding them all like that. Anybody know how that formula works?
TIA
$133,590Screw_Michigan wrote:There's this guy who is making money by wearing t-shirts of companies who pay him to wear their logo. His pricing goes like this. You rent by the day. For example, 1/1 costs $2, but it goes up $2 every day afterward, so on 1/31, that day would cost you $62. The last day of the year, 12/31, that day would cost you $730.
That's why I want to figure out 2+4+6+8+10...., basically up to 365 times, to figure out how much he'd gross if he sold out every single day, and he's close to that.
Thanks. So what's the formula for that?Smackie Chan wrote:$133,590Screw_Michigan wrote:There's this guy who is making money by wearing t-shirts of companies who pay him to wear their logo. His pricing goes like this. You rent by the day. For example, 1/1 costs $2, but it goes up $2 every day afterward, so on 1/31, that day would cost you $62. The last day of the year, 12/31, that day would cost you $730.
That's why I want to figure out 2+4+6+8+10...., basically up to 365 times, to figure out how much he'd gross if he sold out every single day, and he's close to that.
I just used Excel. Enter 2, 4, 6 in the first three cells of a column, then drag the lower right corner of those three highlighted cells down to row 365. Excel will auto-fill the rest of the cells. In any empty cell, enter "=sum(top cell #:botttom cell #)", then enter. Voila!Screw_Michigan wrote:So what's the formula for that?
Nice way to tempt the Reaper you old fuck...you are getting close enough to the exit door and then you decide to fuck around with chemicals based upon Google research...way to jack up the odds....Wolfman wrote: My latest job requires me to make up chemical solutions of varying molarity, etc.. I l last studied chemistry in 1958, Google is my best friend.
Screw_Michigan wrote:Thanks. So what's the formula for that?Smackie Chan wrote:$133,590Screw_Michigan wrote:There's this guy who is making money by wearing t-shirts of companies who pay him to wear their logo. His pricing goes like this. You rent by the day. For example, 1/1 costs $2, but it goes up $2 every day afterward, so on 1/31, that day would cost you $62. The last day of the year, 12/31, that day would cost you $730.
That's why I want to figure out 2+4+6+8+10...., basically up to 365 times, to figure out how much he'd gross if he sold out every single day, and he's close to that.
Group the numbers and get their totals this way:Screw_Michigan wrote:How do you figure?Goober McTuber wrote:I don’t know how to do it with a formula, but I do know from a 20-second exercise with a calculator that that pattern will never land on 730.
5,050, right? If you take out 100 and 50, you have 49 sets of numbers that will add to 100.Smackie Chan wrote:The one thing I remember about Gauss was that he was able to provide his teacher with an answer to the sum of all the numbers from 1 to 100 in a matter of seconds, which is pretty simple, actually.Wolfman wrote:Wasn't that one of the formulas that Karl Friedrich Gauss figured out in Kindergarten ?
Took me a few tries to figure this one out, but was able to get it in 5-10 minutes.
That works, but there's a slightly easier way. There are 50 pairs of numbers that add up to 101, so 101 x 50 = 5050.Killian wrote:5,050, right? If you take out 100 and 50, you have 49 sets of numbers that will add to 100.
49*100=4900
+100
+50
=5050